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... p } , . , we show that \ t - 110 = 1 ( using for , example the p - adic representation ) , and then : | t1199 | dt11n ( p – 1 ) p - bs til < / p - p - bs In ...
... P ] . For P = < 1 > we have nothing to prove . Let | P ≥ p and M a maximal subgroup of P. Then M is normal in P with | P : M = p . Put U : = Cv ( M ) . Let y Є ...
... p - group , there exists a subgroup S of index p in L such that T ≤ S. Finally , S is open because T is open . The pro - p completion Lp of L is defined to ...
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... P + 2 We may now follow the proof of Theorem 1 until the statement " if B ... p and of degree ap in G applies to any intransitive group generated by ...
... p-adic Lie algebras, Proceedings of the International Congress of Mathematicians, Vol. II (Berlin, 1998). Doc. Math. 1998, Extra Vol. II, pp. 553–562 ...
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